[Intel-wired-lan] [PATCH RFC 3/5] sched/cpufreq: Fix incorrect RCU API usage
Peter Zijlstra
peterz at infradead.org
Thu Feb 21 16:11:44 UTC 2019
On Thu, Feb 21, 2019 at 07:52:18AM -0800, Paul E. McKenney wrote:
> On Thu, Feb 21, 2019 at 04:31:17PM +0100, Peter Zijlstra wrote:
> > On Thu, Feb 21, 2019 at 10:21:39AM -0500, Joel Fernandes wrote:
> > > On Thu, Feb 21, 2019 at 10:18:05AM +0100, Peter Zijlstra wrote:
> > > > On Thu, Feb 21, 2019 at 12:49:40AM -0500, Joel Fernandes (Google) wrote:
> > > > > @@ -34,8 +34,12 @@ void cpufreq_add_update_util_hook(int cpu, struct update_util_data *data,
> > > > > if (WARN_ON(!data || !func))
> > > > > return;
> > > > >
> > > > > - if (WARN_ON(per_cpu(cpufreq_update_util_data, cpu)))
> > > > > + rcu_read_lock();
> > > > > + if (WARN_ON(rcu_dereference(per_cpu(cpufreq_update_util_data, cpu)))) {
> > > > > + rcu_read_unlock();
> > > > > return;
> > > > > + }
> > > > > + rcu_read_unlock();
> > > > >
> > > > > data->func = func;
> > > > > rcu_assign_pointer(per_cpu(cpufreq_update_util_data, cpu), data);
> For whatever it is worth, in that case it could use rcu_access_pointer().
> And this primitive does not do the lockdep check for being within an RCU
> read-side critical section. As Peter says, if there is no dereferencing,
> there can be no use-after-free bug, so the RCU read-side critical is
> not needed.
On top of that, I suspect this is under the write-side lock (we're doing
assignment after all).
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