[Intel-wired-lan] [PATCH S23 v2 03/15] ice: Assume that more than one Rx queue is rare in ice_napi_poll
Tony Nguyen
anthony.l.nguyen at intel.com
Fri Jun 28 15:03:21 UTC 2019
From: Brett Creeley <brett.creeley at intel.com>
Currently we divide budget by the number of Rx queues per Rx ring
container in ice_napi_poll even if there is only 1. This is an
unnecessary divide for the normal case of 1 Rx ring per Rx ring
container. Fix this by using an unlikely() call in the case where we
actually need to divide.
Also, we will always set budget_per_ring even if there are no Rx rings
in the Rx ring container so we don't need to initialize it to 0.
Signed-off-by: Brett Creeley <brett.creeley at intel.com>
---
drivers/net/ethernet/intel/ice/ice_txrx.c | 15 ++++++++++-----
1 file changed, 10 insertions(+), 5 deletions(-)
diff --git a/drivers/net/ethernet/intel/ice/ice_txrx.c b/drivers/net/ethernet/intel/ice/ice_txrx.c
index f625d9887f88..7229dea0b83f 100644
--- a/drivers/net/ethernet/intel/ice/ice_txrx.c
+++ b/drivers/net/ethernet/intel/ice/ice_txrx.c
@@ -1717,8 +1717,8 @@ int ice_napi_poll(struct napi_struct *napi, int budget)
container_of(napi, struct ice_q_vector, napi);
struct ice_vsi *vsi = q_vector->vsi;
bool clean_complete = true;
- int budget_per_ring = 0;
struct ice_ring *ring;
+ int budget_per_ring;
int work_done = 0;
/* Since the actual Tx work is minimal, we can give the Tx a larger
@@ -1737,11 +1737,16 @@ int ice_napi_poll(struct napi_struct *napi, int budget)
if (budget <= 0)
return budget;
- /* We attempt to distribute budget to each Rx queue fairly, but don't
- * allow the budget to go below 1 because that would exit polling early.
- */
- if (q_vector->num_ring_rx)
+ /* normally we have 1 Rx ring per q_vector */
+ if (unlikely(q_vector->num_ring_rx > 1))
+ /* We attempt to distribute budget to each Rx queue fairly, but
+ * don't allow the budget to go below 1 because that would exit
+ * polling early.
+ */
budget_per_ring = max(budget / q_vector->num_ring_rx, 1);
+ else
+ /* Max of 1 Rx ring in this q_vector so give it the budget */
+ budget_per_ring = budget;
ice_for_each_ring(ring, q_vector->rx) {
int cleaned;
--
2.20.1
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