[Intel-wired-lan] [PATCH S23 v2 03/15] ice: Assume that more than one Rx queue is rare in ice_napi_poll

[Bowers, AndrewX]

> -----Original Message-----
> From: Intel-wired-lan [mailto:intel-wired-lan-bounces at osuosl.org] On
> Behalf Of Tony Nguyen
> Sent: Friday, June 28, 2019 8:03 AM
> To: intel-wired-lan at lists.osuosl.org
> Subject: [Intel-wired-lan] [PATCH S23 v2 03/15] ice: Assume that more than
> one Rx queue is rare in ice_napi_poll
> 
> From: Brett Creeley <brett.creeley at intel.com>
> 
> Currently we divide budget by the number of Rx queues per Rx ring
> container in ice_napi_poll even if there is only 1. This is an unnecessary divide
> for the normal case of 1 Rx ring per Rx ring container. Fix this by using an
> unlikely() call in the case where we actually need to divide.
> 
> Also, we will always set budget_per_ring even if there are no Rx rings in the
> Rx ring container so we don't need to initialize it to 0.
> 
> Signed-off-by: Brett Creeley <brett.creeley at intel.com>
> ---
>  drivers/net/ethernet/intel/ice/ice_txrx.c | 15 ++++++++++-----
>  1 file changed, 10 insertions(+), 5 deletions(-)

Tested-by: Andrew Bowers <andrewx.bowers at intel.com>